Snowmobiles Many Is there any way to solve this question OTHER THAN Guess and Check?
I have the answer to this problem already but I solved it using guess-and-check.
What's the most concise way to solve this prob?
Wayne is building a shed in his backyward to store his snowmobile. Value Hardware sells 3-in finishing nails for $.99/lb. and 2-in finishing nails for $1.39/lb. Wayne needs 5 lbs of nails. If his bill totals $6.15, how many pounds of each size did he buy?
Make equations out of the information given.
Let x be the number of 3-inch finishing nails in pounds
Let y be the number of 2-inch finishing nails in pounds
The total weight is 5 pounds so x+y = 5
the total price is $6.15, so 0.99x + 1.39y = 6.15
Solve this system of 2 equations in 2 unknowns to get your answer.
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On a recent snowmobile trip, Glenn drove his snowmobile at a rate of 15mph. Heidi followed Glenn leaving 2 hours later from the same place. She rode at a rate of 22mph. How many hours did it take Heidi to catch up to Glenn?????
Everyone is WAAAY off the mark here. I'm still working on it, but it's at least 6 hours all together. (Includes the two hours when Heidi was sat in the lodge watching TV whilst Glenn got on with it)
EDIT:
It's around about the 6 Hours, 20 minute mark. Need help though! Also, depends on the specifics of the question. It could be 4 hours 20 min, because that's how long Heidi took, and not 6 hours 20 min, as that's the total time.
At 6 hours 15 min -
Glenn has travelled 93.75 miles
Heidi has travelled 93.5 miles
At 6 hours 20 min -
Glenn has travelled 95 miles
Heidi has travelled 95.33333333 miles
Come on people, someone must know how to do this better (and quicker). Gone are my maths and formulae days...
EDIT 2: - Done it!!!
At the time Heidi starts, Glenn will be at the
15*(120/60) = 30 mile mark. Let a clock start running just as Glenn reaches the 30 mile mark. Let t be the clock time in hours. Glenn will be at the 30 + 15t mark and Heidi will be at the 22t mark when the clock reads t hours.
To find out when Heidi catches up, we look for the t for which
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